50AMP 2 pole 3 wire grounding 3 pole 3 wire 3 pole 4 wire grounding 4 wire 50 AMP 125V 250V 277V 125/250V 30 250V 125/250V 30 250V 30 120/ 208V Receptical 5-50R 6-50R 7-50R 22 indicates 277/480 VAC, three phase, five wire, four pole 23 indicates 347/600 VAC, three phase, five wire, four pole x is the position occupied by L for locking Dividethe total amps by three for three-phase current, and by two for single-phase current. Multiply the result by the supply voltage, and again by 1,000 for kilowatts required. Add the power in kilowatts used by each emergency safety system according to articles 700, 701, 702 and 708 of the NEC to the kilowatts required to obtain full load Aheater is a device that protects a motor from thermal overloads due to excess current in the windings. According to the NEC, the overload rating must not exceed 115% of the full-load current of the motor. For example, the full-load current of a 10 HP motor at 230V is 28 Amps. Therefore, the heater must be sized for 28 * 1.15 = 32.2 Amps. Ifthe wire is capable of delivering 30 amps, then the power that's being delivered is 208 volts times 30 amps times 1.732 for total power available of 10.8 kVA. In comparison, for a single-phase 30 amp circuit carrying 208 volts, you will only get 6.2 kVA. Basically, 3 phase delivers more power. Toconvert 3-phase kW to amps per phase, you can use the formula: Amps (I) = (kW × 1,000) / (sqrt (3) × Volts) Where: Amps (I) is the current in amperes per phase. kW is the power in kilowatts. sqrt (3) is the square root of 3. Volts is the voltage of the 3-phase system. Wecalculate the apparent power of a three-phase circuit in terms of phase current and phase voltage as: S = 3 × V Ph × I Ph, where: S is the apparent power; VPh is the phase voltage; and IPh is the phase current. 💡 Apparent power is measured in volt-ampere ( VA ). S(VA) = Apparent Power in VA. Therefore, I (A) = S (VA) / V (V) In simple words, Amp = VA / Volts. Three Phase VA to Amps Formula: Three-phase apparent power is equal to three times of single-phase Apparent power while considering Line to neutral voltage. In case while considering line to line voltage, the VA will be the 1.732 times of the Forthree phase amperage - FORGET the term "Total Current". That concept is useless. If the three phases are reasonably balanced - list that current. For example, if A = 5.1A, B = 5.0A, C = 5.2A, you would say, "The current is 5.1A" That phrase means the currents are reasonably balanced and 5.1A is an average number. HbYtqV.